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Mathematical Reasoning
normal
The converse of the statement "If $p < q$, then $p -x < q -x"$ is -
A
If $p < q,$ then $p -x > q -x$
B
If $p > q$, then $p -x > q -x$
C
If $p -x > q -x,$ then $p > q$
D
If $p -x < q -x,$ then $p < q$
Solution
Converse of $p \rightarrow q,$ is $q \rightarrow p$
Standard 11
Mathematics