Mathematical Reasoning
normal

The converse of the statement "If $p < q$, then $p -x < q -x"$ is -

A

If $p < q,$ then $p -x > q -x$

B

If $p > q$, then $p -x > q -x$

C

If $p -x > q -x,$ then $p > q$

D

If $p -x < q -x,$ then $p < q$

Solution

Converse of $p \rightarrow q,$ is $q \rightarrow p$

Standard 11
Mathematics

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